疑問 - 一個小遊戲的程式 該怎麼寫???

[rang0419]

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閱讀本主題的最佳解答
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可以請問一下 下面的小遊戲該怎麼寫呢.......


有高手可以借我參考一下嗎........


感激不進!!


Create a tic-tac-toe game.

(1) First display a welcome message to the game. A player enters her or his name, selects to play first or not, and then start to plays the game.
(2) Display a 3 by 3 tic-tac-toe board.
(3) The player selects the cell to mark. The computer randomly selects the cell to mark.
(4) The game is continuing until there is a winner or the game is tie.
(5) Display the winning points for the winner which are the total of 3 different numbers between 1 and 9 random generated by the computer.
(6) The player can choose to continue a new game.

Hint: Refer to the following code.
welcome (char name[]) {
printf("===========================================\n");
printf("Welcome to the tic-tac-toe game! \n");
printf("Your name: ");
scanf("%s", name);
printf("%s, welcome to the game!\n", name);
printf("===========================================\n");
}

draw_box() {
char box[3][3] = {{'+', '-', '+'}, {'|', ' ', '|'}, {'+', '-', '+'}};
int i, j;

for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) printf("%c", box[i][j]);
printf("\n");
}
}

main() {
char name[40];

welcome(name);
draw_box();
}


A possible run may look like as follows:
===========================================
Welcome to the tic-tac-toe game!
Your name: Rita
Rita, welcome to the game!
===========================================
a b c
1 | |
---+---+---
2 | |
---+---+---
3 | |

Rita, do you want to play first (Y/N)? Y
Rita's step => 2b /* input by the user */

a b c
1 | |
---+---+---
2 | o |
---+---+---
3 | |

Computer's step => 1a /* generated by the computer */

a b c
1 x | |
---+---+---
2 | o |
---+---+---
3 | |

Rita's step => 3c

a b c
1 x | |
---+---+---
2 | o |
---+---+---
3 | | o

Computer's step => 3a

a b c
1 x | |
---+---+---
2 | o |
---+---+---
3 x | | o

Rita's step => 2a

a b c
1 x | |
---+---+---
2 o | o |
---+---+---
3 x | | o

Computer's step => 1c

a b c
1 x | | x
---+---+---
2 o | o |
---+---+---
3 x | | o

Rita's step => 2c

a b c
1 x | | x
---+---+---
2 o | o | o
---+---+---
3 x | | o

===========================================
Congratulations! Rita is the winner.
Your lucky numbers are 7, 5, and 2.
Rita's points: 14
Computer's points: 0
Play more (Y/N)? Y
===========================================

[rang0419]

忘了說 要用C來寫 囧

[mini]

這主要有兩部分
Computer的人工智慧 與 判斷輸贏結束

人工智慧方面
設計一個亂數選擇能用的空格去填
是最簡單的
算式:
Int((upperbound - lowerbound + 1) * Rnd + lowerbound)
，請自行改成C

至於判斷輸贏結束
首先是
判斷是否連成一線 (是的話結束並推論由誰贏 ※最後下手的人贏)
<土法煉鋼>
掃描第一行(1a、1b、1c)、第二行(類推)、第三行(類推)
接著掃描1a、2b、3c
最後掃描1c、2b、3a

再來是計數
第一手的玩家 是否下了5次
是的話結束(可能不分輸贏)

[rang0419]

作者: mini

這主要有兩部分
Computer的人工智慧 與 判斷輸贏結束

人工智慧方面
設計一個亂數選擇能用的空格去填
是最簡單的
算式:
Int((upperbound - lowerbound + 1) * Rnd + lowerbound)
，請自行改成C

至於判斷輸贏結束
首先是
判斷是否連成一線 (是的話結束並推論由誰贏 ※最後下手的人贏)
<土法煉鋼>
掃描第一行(1a、1b、1c)、第二行(類推)、第三行(類推)
接著掃描1a、2b、3c
最後掃描1c、2b、3a

再來是計數
第一手的玩家 是否下了5次
是的話結束(可能不分輸贏)

恩恩!!! 感謝提醒喔~~~

我在研究看看~~~